Ferguson: Wayne Rooney will play in Romania

Ferguson: Rooney will play in Romania
© PA Photos
Sir Alex Ferguson confirms Wayne Rooney will feature for Manchester United in their Champions League tie with Otelul Galati tomorrow night.

Sir Alex Ferguson has revealed Wayne Rooney will feature for Manchester United in their Champions League match against Otelul Galati tomorrow night.

Rooney was left on the bench for United's 1-1 draw with rivals Liverpool at Anfield on Saturday after Ferguson had admitted the striker "has had a bad week".

The 25-year-old had been dealt a three-match suspension by UEFA after his sending-off during England's European Championship qualifier with Montenegro earlier this month.

"When he came on against Liverpool he was quite bubbly. He was full of energy and enthusiasm. He was desperate to get on, which is good," said Ferguson.

"Wayne will be playing tomorrow."

United are looking for their first win in this year's competition after draws against Benfica and FC Basle in their opening two group games.

Wayne Rooney, Nemanja Vidic
Read Next:
Rooney, Vidic to make United return
>
You May Like
Recomended from Sports Mole



Tables
TeamPWDLFAGDPTS
1Manchester CityMan City98103242825
2Manchester UnitedMan Utd96212241820
3Tottenham HotspurSpurs96211961320
4Chelsea95131710716
5Arsenal95131712516
6Watford94321517-215
7Newcastle UnitedNewcastle9423108214
8Burnley934289-113
9Liverpool93421416-213
10Southampton933389-112
11Huddersfield TownHuddersfield9333710-312
12Brighton & Hove AlbionBrighton9324910-111
13West Bromwich AlbionWest Brom9243710-310
14Leicester CityLeicester92341214-29
15Swansea CitySwansea9225610-48
16West Ham UnitedWest Ham9225817-98
17Stoke CityStoke92251020-108
18Everton9225718-118
19Bournemouth9216613-77
20Crystal Palace9108219-173
LIVE SCORES VIDEPRINTER
expand