Canadian number one Milos Raonic is through to round two of the 2014 Australian Open after beating Spain's Daniel Gimeno-Traver 7-6 6-1 4-6 6-2.
Four breaks of serve were shared in the opening set, which eventually went the way of 11th seed Raonic, who prevailed 7-2 in a tie-break.
After a very close first set, the second was fairly one-sided as Raonic won 29 of 44 points, including 12 of 16 on his serve.
Both players won 27 points in a competitive third set, which Gimeno-Traver edged courtesy of a solitary break.
Raonic then went up a gear in the fourth, recording eight aces, 12 winners and just five unforced errors to secure his place in the second round, where he will face Romania's Victor Hanescu.
Written by
Robert Summerscales
Robert Summerscales
